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Overlap control gives a union lower bound
Statement
Let be finitely many events in a probability space, put , and suppose that for a real number Then Both quantities vanish when ; no hypothesis is imposed on the individual probabilities beyond , and the bound is uniform over all finite families with the stated overlap ratio.
Facts & Assumptions
Given: events on a probability space, the sum , and a real with .
For vectors in a real or complex inner product space, ; applied to the indicator functions of two events in of a finite probability space this is the inequality for random variables, and for a nonnegative integer-valued it gives , since off the event (Cauchy–Schwarz: , with equality exactly for linearly dependent vectors).
Proof
Let count the events that occur. Then is integer valued, with by linearity of expectation, and .
Expanding the square, , so taking expectations and using the hypothesis gives , a finite bound.
If then with , so every , almost surely, and both sides of the claimed inequality are zero; assume from now on. Applying [L1] to and to the indicator of gives . Dividing by the positive number gives , which is the claim.
Remarks
- The hypothesis is a ratio condition, not a smallness condition on the intersections separately: the bound is useful exactly when is uniformly bounded, and then it loses only the factor relative to the first moment .
- The Arora-Barak form of the same estimate (Claim 18.34) counts elements of finite sets, makes copies of each element and reduces to inclusion-exclusion, with the weaker constant and a hypothesis on the diameter of the set system; the probabilistic second-moment computation above is the convention of this page, and it applies directly to the events of Powering amplifies a small unsatisfaction gap, whose pair overlaps are controlled by Violated-edge positions have controlled collisions.
- The constant is sharp already for two disjoint events: then , and the union has probability exactly .
Depends on
Used by
Dependency tree · two levels
6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Arora and Barak, Computational Complexity: A Modern Approach, §18.5.1 Claim 18.34 and its counting proof, printed pp. 376-377. (standard reference, not scraped)
- Irit Dinur, The PCP theorem by gap amplification, §6 equation (7) and Fact 2.6, printed pp. 21-22. (standard reference, not scraped)