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The parameter power-series map is injective by dimension

Statement

Assume the Axiom of Dependent Choice.

Let (A,m) be a complete equicharacteristic Noetherian local domain of dimension d, let kA be a coefficient field, and let x1,,xd be a system of parameters. Then the continuous map ϕ:kX1,,XdA,Xixi, is injective.

Facts & Assumptions

Given: A complete equicharacteristic Noetherian local domain (A,m) of dimension d, a coefficient field k, a system of parameters x1,,xd, and the Axiom of Dependent Choice.

[L3]

The formal power-series ring kX1,,Xd is a Noetherian local domain of dimension d (Stacks Project, Section 10.160, Remark 10.160.9).

[L4]

A strict chain of primes contracts to a strict chain along an integral injection (Strict prime chains contract strictly under integral extensions).

Proof

technique · a nonzero kernel would force the source quotient to have dimension less than the target
1.1

Let B=kX1,,Xd and suppose P:=ker(ϕ)0. Since A is a domain, P is prime. By [L1], A is finite over the image B/P, hence integral over B/P.

L1givenassume-contraalgebra
2.1

By [L3], B is a domain of dimension d. Every strict chain of primes in B/P lifts to a strict chain of primes of B containing P; adjoining P at the bottom if necessary, write it as P=p0p1p. This chain can be preceded by the strict inclusion (0)P. Hence +1d, and therefore dim(B/P)d1.

L3step 1.1algebra
3.1

By [L4], every strict chain of primes in A contracts to a strict chain in B/P, so dimAdim(B/P). Combining this with step 2.1 gives d=dimAd1, contradicting [L2].

L2L4step 1.1step 2.1discharge-contradiction
4.1

Therefore ker(ϕ)=0, so ϕ is injective.

step 3.1

Depends on

Used by

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