How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Consistency transfers from IID mixture samples to permuted groups
Statement
Assume AC. Let be probability laws and let , with . Write . For each , let be a measurable statistic of observations and let be a deterministic target. If
then applied to either group of a uniform random permutation of the pooled independent sample , also converges in probability to . The statement does not require because the IID comparison law uses the exact weight .
Facts & Assumptions
Given: Independent IID samples from and , a uniform permutation of their pooled observations, and an estimator/statistic consistent for on IID samples of the same group size.
Hypergeometric and binomial composition counts are contiguous: the hypergeometric label count in a size- permuted group is contiguous to the binomial label count in a size- IID mixture sample.
Identical distribution and IID families: each source group is IID with its stated common law.
Independent random elements: the source groups and the random subset selection are independent as specified.
Statistics and estimators: a statistic is a measurable function of the ordered observations; an estimator is such a statistic with a specified target.
AC is inherited from the likelihood-ratio contiguity result [F1]. The Axiom of Choice
Proof
Given: The assumptions in the Statement. Prove consistency for both permuted group sizes.
Fix equal to either or . In an IID sample from , the number of observations whose mixture component is has law . In a uniformly chosen size- group from the pooled sample with exactly -observations among , the corresponding count is hypergeometric.
Conditional on either count being , the ordered group has the same distribution: its -positions are uniform among the -subsets of the positions, the values at those positions are IID , and the remaining values are IID . Therefore there is a function giving the conditional probability that under either sampling scheme.
The IID mixture consistency assumption gives . Markov's inequality implies in probability under the binomial law. By contiguity [F1], in probability under the hypergeometric law. Since , this also gives . AC is used through [F1] only.
By step 1.2, is exactly the probability that the statistic differs from by more than for the randomly permuted size- group. This tends to zero. The argument applies separately to and , proving the assertion.
Depends on
Used by
Dependency tree · two levels
21 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- E. Y. Chung and J. P. Romano, Exact and Asymptotically Robust Permutation Tests, Stanford Technical Report 2011-05, Lemma 3.3 and proof (standard reference, not scraped)