Alphabeta Math
LemmaStatement: Literature-sourcedProof: Literature-sourcedprecheck passaudited 2026-08-11
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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The monic gcd of two base-field polynomials is unchanged after extending the coefficient field

Statement

Let F⊆E be a field extension and let f,g∈F[x] be not both zero. The monic gcd of f and g computed in F[x] is also their monic gcd in E[x].

Facts & Assumptions

Given: A subfield F⊆E and polynomials f,g∈F[x] not both zero.

[L1]

The monic gcd is the unique monic common divisor divisible by every common divisor (The monic greatest common divisor of two polynomials over a field).

[L2]

If d=gcd⁡(f,g) in F[x], then d=Af+Bg for some A,B∈F[x] (Bézout identity and the Euclidean algorithm for polynomials over a field).

[L3]
[L4]

A coefficient inclusion extends uniquely to a ring homomorphism of polynomial rings (Universal property of R[x]: a coefficient homomorphism and the image of x determine a unique ring homomorphism).

Proof

technique · direct
1.1

Let d be the monic gcd in F[x]; it divides f,g there and hence in E[x] under [L4], while [L2] remains the identity d=Af+Bg in E[x] by [L3] and [L4].

givenL1L2L3L4
2.1

Every common divisor of f,g in E[x] divides the right side of the Bézout identity and hence divides d; since d is monic, [L1] identifies it as the monic gcd computed in E[x].

step 1.1L1L2∎

Depends on

Used by

Dependency tree · two levels

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Sources