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Every rank-r orthogonal projector is an admissible density

Statement

Every P∈Pr belongs to the admissible density domain Dr.

Facts & Assumptions

Given: P∈Hn satisfies P=P∗, P2=P, and tr⁡P=r, where 1≤r<n.

[F1]

The rank-r projector set is Pr={P=P∗:P2=P,tr⁡P=r} (Rank-r orthogonal projector domain).

[F3]

The admissible domain consists of Hermitian positive contractions of trace r (The fixed-particle admissible Hermitian density domain).

Proof

1.1givenF1F2algebra

By [F2], choose a unitary eigenbasis of P with real eigenvalues μj. From P2=P, each satisfies μj2=μj, hence μj∈{0,1}. Therefore every eigenvalue lies between 0 and 1, so for each x the quadratic forms x∗Px and x∗(I−P)x are nonnegative.

2.1step 1.1F1F3∎

The matrix P is Hermitian and has trace r by [F1]; step 1.1 gives 0⪯P⪯I. These are exactly the conditions in [F3], so P∈Dr.

Depends on

Used by

Cited to discharge well-definedness by The fixed-particle admissible Hermitian density domain.

Dependency tree · two levels

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