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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generated
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Grover eigenphases encode the good probability

Statement

Let ψ=A∣0⟩, a=∥Πgoodψ∥2, and θ=arcsin⁡a. If 0<a<1, define the unit vectors G=Πgoodψ/a and B=(I−Πgood)ψ/1−a. In the ordered basis (B,G), the Grover iterate Q of Amplitude estimation and counting input/output contract restricts to (cos⁡(2θ)−sin⁡(2θ)sin⁡(2θ)cos⁡(2θ)). Its eigenvalues are e2iθ and e−2iθ, and ψ=cos⁡θB+sin⁡θG has squared overlap 1/2 with each corresponding normalized eigenvector. At a=0, ψ is a +1 eigenvector; at a=1, it is a −1 eigenvector.

Facts & Assumptions

Given: The unitary A, the orthogonal good projection, the state ψ=A∣0⟩, and the signed iterate Q=−AS0A∗Sgood.

[F1]

The definitions of S0, Sgood, Q, a, and θ are fixed in Amplitude estimation and counting input/output contract.

[F2]

The signed iterate leaves the good/bad plane invariant and has matrix (cos⁡(2θ)−sin⁡(2θ)sin⁡(2θ)cos⁡(2θ)) in the ordered (B,G) basis (Amplitude-amplification invariant plane).

Proof

1.1givenF1F2algebra

When 0<a<1, the definition in [F1] has 1−a=cos⁡θ and a=sin⁡θ because θ∈(0,π/2). The supplier matrix in [F2] therefore applies to the same ordered basis and the same signed Q defined in [F1].

2.1F2step 1.1algebra

For that matrix, the characteristic polynomial is λ2−2cos⁡(2θ)λ+1, with roots cos⁡(2θ)±isin⁡(2θ)=e±2iθ. The normalized vectors (B−iG)/2 and (B+iG)/2 are eigenvectors for these roots. Their inner products with ψ=cos⁡θB+sin⁡θG have squared modulus (cos⁡2θ+sin⁡2θ)/2=1/2.

3.1F2algebra∎

At a=0, [F2]’s endpoint statement gives Qψ=ψ, with phase 0 modulo one. At a=1, it gives Qψ=−ψ=e2πi(1/2)ψ, with phase 1/2. These are the remaining endpoint eigenphases and require no zero component normalization.

Depends on

Used by

Dependency tree · two levels

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Sources