Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Effective spectral gap for a product of two reflections

Statement

Let H be a finite-dimensional complex inner-product space, Π and Δ orthogonal projections on H, R_Π=2Π-I and R_Δ=2Δ-I, and U=R_ΠR_Δ. For 0≤ω≤π, let E_ω be the spectral projection of U onto eigenvalues e^{iφ} whose principal arguments satisfy |φ|≤ω. If Δw=0, then ∥EωΠw∥≤ω2∥w∥.

Facts & Assumptions

Given: The finite-dimensional projections and vector w in the Statement, with Δw=0.

[F1]

Orthogonal-Projector Reflection and Access Contract: for an orthogonal projection P, the plus-on-range reflection is R_P=2P-I.

[F2]

Projector Reflections Are Hermitian Unitary Involutions: each such reflection is a unitary involution.

[F3]

Proof

1.1givenF1algebra

Put R_P=2P-I and R_D=2D-I. Since D w=0, R_D w=-w; hence U w=R_P R_Dw=-R_Pw and therefore P w=(w+R_Pw)/2=(I-U)w/2.

2.1givenF2F3step 1.1algebra

Let E_ω be the orthogonal spectral projection of U onto eigenvectors with eigenvalue e^{iφ} for a principal phase φ∈[-π,π] satisfying |φ|≤ω. By [F2], both reflections are unitary, so U is unitary. By [F3], E_ω commutes with U and has an orthonormal eigenbasis. Thus E_ω P w=(I-U)E_ωw/2, and on each selected eigenvector |1-e^{iφ}|≤|φ|≤ω. The squared norm in that basis is at most (ω/2)^2||E_ωw||²≤(ω/2)^2||w||².

3.1givenF1step 1.1step 2.1∎

Taking square roots proves ||E_ωP w||≤ω||w||/2, including zero- and full-rank projections because step 1.1 used only the projection identities.

Depends on

Used by

Dependency tree · two levels

26 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources