Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-sol)audited 2026-09-30
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Random binary subsums detect every nonzero discrepancy

Statement

For every nonzero d∈F2m and uniform z∈F2m, Pr⁡[z⋅d=1]=12. The same conclusion applies whenever d is a nonzero vector of violated quadratic equations or the difference of two distinct decoded prefixes.

Facts & Assumptions

Given: A nonzero binary vector d∈F2m and the uniform distribution on the finite cube.

[F1]

Distinct Walsh–Hadamard messages in dimension m≥1 have tables that disagree on exactly half the coordinates. (Distinct Walsh–Hadamard words differ on half the cube)

Proof

1.1givenconstructalgebra

Since d≠0, choose the least index j with dj=1, and let ej be its unit vector. The map z↦z+ej is a fixed-point-free involution of the cube and (z+ej)⋅d=z⋅d+1, so it pairs each outcome with one whose dot product has the opposite bit.

2.1F1step 1.1algebradischarge-construct∎

Each pair from step 1.1 has exactly one vector with z⋅d=1, hence exactly 2m−1 of the 2m vectors satisfy the event and its uniform probability is 1/2. Equivalently these are precisely the coordinates where WH⁡m(0) and WH⁡m(d) disagree, consistent with the half-distance lemma in [F1]. Thus every nonzero violated-equation vector and every difference of distinct prefixes has the same detection probability; the number and correlations of its coordinates are irrelevant.

Depends on

Used by

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources