Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedverified 2026-09-26 (gpt-6-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The read-only-workspace diagonal machine halts

Statement

Let s be work-space constructible with log⁡(n+2)=O(s(n)). The local read-only-workspace diagonal simulator can stop every deterministic computation after its finite configuration bound while using O(s(n)) work space.

Facts & Assumptions

Given: the stated constructible bound. For varying machine descriptions, use the uniform encoded-storage cap of Universal simulation preserves read-only work space up to constants; for a fixed machine, its visited-cell cap gives the same asymptotic bound with a machine-dependent constant.

Proof

technique · direct
1.1givenconstruct

Compute s(n) in O(s(n)) work space, simulating the constructibility machine on a virtual unary input of length n if necessary. For varying descriptions, reject when the universal simulator's entire encoded configuration and scratch storage would exceed s(n) cells. A configuration below this cap is described by O(s(n)) bits, together with O(log⁡(n+2)) bits for input and program addresses. Thus the number of possible configurations is at most 2O(s(n)+log⁡(n+2))=2O(s(n)). The cap may reject a computation before this bound is reached.

2.1step 1.1algebra∎

Use the uniform encoded-storage simulator and a binary counter of O(s(n)) bits to count through this configuration bound, stopping at expiry or an earlier storage overflow. A deterministic computation that remains within the cap and has not halted by then must repeat a configuration. The forced answer therefore makes the simulation total while the simulator, counter, and address bookkeeping together use O(s(n)) work space. For a fixed machine the visited-cell version of the supplier gives the analogous bound.

Depends on

Used by

Dependency tree · two levels

4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources