Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Every point of a 2-design lies in the same number of blocks

Statement

Let (P,B) be a 2-(v,k,λ) design. Then there is a natural number r such that every point of P lies in exactly r blocks.

Facts & Assumptions

Given: A 2-(v,k,λ) design (P,B).

[L1]

Every block has exactly k points, with 2≤k<v and λ≥1 (A 2-(v,k,λ) design).

[L2]

Every two-element subset of P lies in exactly λ blocks (A 2-(v,k,λ) design).

Proof

technique · direct
1.1givenchoose

Fix a point p∈P, and let rp be the number of blocks containing p. Count the ordered pairs (q,B) with q∈P∖{p} and {p,q}⊆B.

2.1step 1.1L1algebra

Counting by blocks through p, each such block contributes k−1 choices of q, so the number of pairs is rp(k−1).

2.2step 1.1L2algebra

Counting by the second point, each q∈P∖{p} contributes exactly λ blocks, so the number of pairs is λ(v−1).

3.1step 2.1step 2.2algebra∎

Therefore rp(k−1)=λ(v−1), so rp=λ(v−1)/(k−1) depends only on v, k, and λ, not on p. Thus every point lies in the same number r of blocks.

Depends on

Used by

Dependency tree · one level

1 result within one dependency step of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources