Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-28
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Every Schreier generator lies in the subgroup

Statement

Let F(X) be a free group, let H≤F(X), and let T be a Schreier system. Then every Schreier generator s(t,x) belongs to H.

Facts & Assumptions

Given: A free group F(X), a subgroup H≤F(X), a Schreier system T, and a Schreier generator s(t,x).

[L1]

By definition, s(t,x)=tx tx‾−1, where tx‾ is the chosen representative of the right coset Htx (Schreier generators in the right-coset convention).

Proof

technique · direct
1.1L1given

Because tx‾ represents the same right coset as tx, one has Htx=Htx‾.

2.1L1step 1.1∎

Right-multiplying the equality of step 1.1 by tx‾−1 gives Hs(t,x)=H. Hence s(t,x)∈H.

Depends on

Used by

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources