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LemmaStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-28
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Every Schreier generator lies in the subgroup

Statement

Let F(X) be a free group, let HF(X), and let T be a Schreier system. Then every Schreier generator s(t,x) belongs to H.

Facts & Assumptions

Given: A free group F(X), a subgroup HF(X), a Schreier system T, and a Schreier generator s(t,x).

[L1]

By definition, s(t,x)=txtx1, where tx is the chosen representative of the right coset Htx (Schreier generators in the right-coset convention).

Proof

technique · direct
1.1

Because tx represents the same right coset as tx, one has Htx=Htx.

L1given
2.1

Right-multiplying the equality of step 1.1 by tx1 gives Hs(t,x)=H. Hence s(t,x)H.

L1step 1.1

Depends on

Used by

Dependency tree · two levels

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Sources