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LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
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Trace functions are regular and conjugation invariant

Statement

Assume full AC. For every word w in the generators of a finitely presented group G, the function ρ↦tr⁡(ρ(w)) is a regular function on Hom⁡(G,SL2(C)) and is invariant under simultaneous conjugation.

Facts & Assumptions

Given: Full AC, a finite presentation of G, its affine representation variety, and a word w in the generators and their inverses.

[F1]

For the given finite presentation, impose determinant-one equations and the matrix-entry relator equations in the finite generator matrix space. By the inverse formula [F2], these are polynomial equations for every finitely presented group, not just a knot group.

[F2]

If A=(abcd)∈SL2(C), then A−1=(d−b−ca), as verified by direct multiplication using ad−bc=1.

Proof

1.1F1F2constructalgebra

The equations of [F1] cut out exactly the representation tuples, since a generator assignment satisfies them precisely when it respects every presented relator. Evaluate w by multiplying its generator matrices and the adjugates for inverse letters from [F2]. Each entry of the resulting matrix is a polynomial in the representation coordinates, so its trace is regular.

2.1step 1.1algebra

For any P∈SL2(C), conjugation sends the word matrix W to PWP−1. The identity tr⁡(PWP−1)=tr⁡(WP−1P)=tr⁡(W) proves invariance.

3.1step 1.1step 2.1∎

Thus each word trace defines an element of the conjugation-invariant coordinate ring of the representation variety.

Depends on

Used by

Dependency tree · two levels

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Sources