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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
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Uniform SMC backward-operator contraction controls oscillation

Statement

Let Es be the forward operators of Finite-horizon SMC CLT classes and variance recursions, and for bounded real h put osc⁡(h)=sup⁡h−inf⁡h. Suppose there is one β∈[0,1) such that osc⁡(Esh)≤βosc⁡(h) for every s and every bounded real h with πs(h)=0, with bounded measurable versions of Esh. The stronger condition on every bounded h is sufficient but is not necessary here. For bounded ϕ:Θt→R, put Δϕ=osc⁡(ϕ) and ϕˉ=ϕ−πt(ϕ). Then for every 0≤k≤t, ∥Ek+1:tϕˉ∥∞≤βt−kΔϕ, with β0=1 and Et+1:t the identity. This condition concerns the actual SMC backward operators; it is not implied merely by mixing ratios of the proposal densities.

Facts & Assumptions

Given: The SMC flow and operators in the Statement, bounded real ϕ, and the uniform operator contraction hypothesis.

[A1]

The Axiom of Choice: AC is inherited through the finite-horizon path and Radon–Nikodym construction.

[F1]

Finite-horizon SMC CLT classes and variance recursions: Esh=ks(υsh), π~s=πs−1ks, and π~s(υsh)=πs(h).

Proof

Given: The hypotheses in the Statement.

1.1A1F1given

For any bounded measurable h and s≥1, [F1] gives πs−1(Esh)=πs−1(ks(υsh))=π~s(υsh)=πs(h). Iterating this identity yields πk(Ek+1:tϕˉ)=πt(ϕˉ)=0 for every k<t; for k=t the identity operator also gives mean zero.

2.1F1step 1.1given∎

Repeated application of the assumed oscillation contraction gives osc⁡(Ek+1:tϕˉ)≤βt−kosc⁡(ϕˉ)=βt−kΔϕ. By step 1.1 its πk-mean is zero, so its infimum is at most zero and its supremum at least zero; hence its sup norm is at most its oscillation. For k=t this is ∥ϕˉ∥∞≤Δϕ.

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Sources