Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A nonzero bounded linear operator is large on one of two nearby points

Statement

Let T:XY be nonzero and bounded (A bounded linear operator between normed spaces), let xX, and let r>0. There is a yB(x,r) such that

Ty>2r3T,

where T is The operator norm as the least bound and as the unit-sphere or unit-ball supremum.

Facts & Assumptions

Given: A nonzero bounded linear operator T, xX, and r>0.

Proof

technique · direct
1.1

The unit-ball definition of the operator norm supplies z with z1 and Tz>8T/9.

givenchoose
2.1

Put w=(3r/4)z. Then both x+w and xw lie in B(x,r), and Tw>2rT/3.

step 1.1algebra
3.1

The triangle inequality applied to T(x+w)T(xw)=2Tw gives max{T(x+w),T(xw)}Tw>2r3T.

step 2.1algebra
4.1

Choosing the corresponding one of x+w,xw proves the claim.

step 2.1step 3.1

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources