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Symmetric matrices are Euclidean under the Frobenius norm

Statement

Let d≥1, let Sd be the real vector space of symmetric d×d matrices, and set m=d(d+1)/2. Use one-based entry labels Aij:=A(i−1,j−1) for 1≤i,j≤d, and likewise for every matrix below. Equip Sd with the Frobenius inner product ⟨A,B⟩F:=∑i=1d∑j=1dAijBij and its induced norm. Define svec⁡:Sd→Rm by listing A11,…,Add first, followed by 2Aij for 1≤i<j≤d in lexicographic order. Then svec⁡ is a linear bijection and preserves inner products and norms; in particular, ∥svec⁡(A)−svec⁡(B)∥2=∥A−B∥F for all A,B∈Sd.

Facts & Assumptions

Given: An integer d≥1, symmetric real matrices A,B∈Sd, and m=d(d+1)/2.

[F1]

For a real matrix, the squared Frobenius norm is the sum of the squares of all entries (The Frobenius norm ∥A∥F=(∑i,j∣aij∣2)1/2 on real or complex matrices). Under the stated entry labels, substituting i=r+1, j=s+1 gives ∑r<d∑s<dA(r,s)2=∑i=1d∑j=1dAij2; in particular, when d=1, A11=A(0,0).

[F2]

The Euclidean inner product on Rm is the coordinate dot product, with norm the square root of the sum of coordinate squares (The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn).

[F3]

Every nonnegative real number has a unique nonnegative square root, so 2>0 and division by 2 is defined (Square roots exist: a unique a≥0 with (a)2=a; the positives are {x2:x≠0}).

Proof

1.1givenF3algebra

The coordinate list has d+d(d−1)/2=m entries. Its first d entries recover each diagonal entry of A, and each later entry recovers the corresponding symmetric pair by division by 2 from [F3]. Thus it has a unique inverse on Rm; its coordinate formulas are linear, so svec⁡ is a linear bijection.

1.2F2givenalgebra

For A,B∈Sd, the Euclidean dot product of their coordinate lists is ∑iAiiBii+2∑i<jAijBij, because each off-diagonal coordinate contributes (2Aij)(2Bij). Symmetry gives ⟨A,B⟩F=∑iAiiBii+∑i<j(AijBij+AjiBji), which is the same expression. Hence ⟨svec⁡(A),svec⁡(B)⟩2=⟨A,B⟩F.

2.1step 1.2F1F2F3algebra∎

Linearity gives svec⁡(A)−svec⁡(B)=svec⁡(A−B). Applying step 1.2 to A−B with itself and taking the unique nonnegative square roots from [F1]–[F3] yields ∥svec⁡(A)−svec⁡(B)∥2=∥A−B∥F. This proves norm preservation.

Depends on

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Sources