Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-08-30
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The kernel of a chain map is computed degreewise

Statement

Let f:C∙→D∙ be a chain map. The kernels ker⁡(fn)↪Cn assemble into a chain complex, and this complex is a kernel of f in Ch⁡(A).

Facts & Assumptions

Given: A chain map f:C∙→D∙.

[L1]

A chain map satisfies dnDfn=fn−1dnC (Chain map).

[L2]

Kernels are universal among arrows annihilated by the displayed map (Kernels and cokernels in a category with zero morphisms as equalizers and coequalizers).

Proof

technique · constructive
1.1L1L2givenconstruct

Let kn:Kn→Cn be a kernel of fn. By [L1], fn−1dnCkn=dnDfnkn=0, so [L2] gives a unique differential dnK:Kn→Kn−1 with kn−1dnK=dnCkn.

2.1L2step 1.1algebradischarge-construct∎

The family K∙ is a chain complex because kn−2dn−1KdnK=dn−1CdnCkn=0, and kn−2 is monic. The map k:K→C is a chain map by construction, and its componentwise kernel universal properties from [L2] together give the kernel universal property in Ch⁡(A).

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources