Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passaudited 2026-09-01
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The preconnecting arrow annihilates boundaries

Statement

For a short exact sequence of complexes, the composite Bn(C)→Zn(C)→∂~nHn−1(A) is zero.

Facts & Assumptions

Given: A short exact sequence 0→A∙→B∙→C∙→0 of complexes and an integer n.

[L1]

The preconnecting arrow is ∂~n=δnsnakeqn, where qn:Zn(C)→Hn(C) is the homology quotient (The preconnecting arrow on cycles).

[L2]

The homology quotient qn is the cokernel of the canonical boundary-to-cycle map βn:Bn(C)→Zn(C) (Homology object of a chain complex).

Proof

technique · direct
1.1L2given

Because qn is the cokernel of βn, one has qnβn=0.

2.1L1step 1.1algebra∎

Using [L1], ∂~nβn=δnsnakeqnβn=0. Thus the composite from the boundary subobject to Hn−1(A) is the zero morphism.

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources