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LemmaStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The translates of a block partition its orbit

Statement

Let G act on Ω, and let BΩ be a block. Then the family TB:={gB:gG} has pairwise equal-or-disjoint members, its union is GB:={gb:gG, bB}, and it is preserved by the action of G. Hence TB is a G-invariant partition of GB.

Facts & Assumptions

Given: A left action of G on Ω and a block BΩ.

[L1]

A block is a nonempty subset B such that for every gG one has either gB=B or (gB)B= (Blocks and block systems for a group action).

Proof

technique · direct
1.1

If gB meets hB, choose x(gB)(hB). Then h1x(h1g)BB, so [L1] gives (h1g)B=B.

L1choose
1.2

By definition every point of TB has the form gb with gG and bB, and every such point lies in the translate gB. So TB=GB.

givenalgebra
2.1

From step 1.1, gB=hB whenever the two translates meet. Thus distinct translates are disjoint.

step 1.1
3.1

For kG one has k(gB)=(kg)B, which is again in TB. Hence G permutes the members of TB, and steps 2.1 and 1.2 make it a G-invariant partition of GB.

step 2.1step 1.2algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources