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A transversal of wide structural blocks yields the pure blockade outcome
Statement
Assume a structural comb partition for an -comb with . If for every one can choose a block with , then is a pure -blockade.
Facts & Assumptions
Given: One selected partition block of size at least for every .
Every partition block is pure to every vertex in every other comb block with (The structural comb-partition hypothesis).
A blockade is a sequence of pairwise disjoint nonempty sets with the stated length and width bounds; a pure blockade has every pair of blocks pure (Blockades, their length, their width, and their support, Complete, anticomplete, pure, weakly sparse, and -sparse blockades).
Proof
The selected sets lie in distinct, hence disjoint, comb blocks. Fix . By [F1], every vertex of is individually complete or anticomplete to . If two such vertices had opposite relations, then any vertex of the nonempty set would be mixed on , contradicting [F1] applied with and reversed. Hence the relation is uniform and the pair of selected blocks is pure.
Thus the selected sequence is a pure blockade of length and width at least by [F2].
Since , , so . Step 2.1 and [F2] give the asserted pure -blockade.
Depends on
Used by
Dependency tree · two levels
10 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Huang, Ju, and Zhou, Erdős–Hajnal beyond the five-vertex path, Claim 5.1.1 (standard reference, not scraped)