Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

r equations lower dimension by at most r

Statement

Let X be an irreducible classical variety of dimension n, and let f1,,fr be global regular functions, with r0. Every nonempty irreducible component Z of their common zero set has dimZnr.

Work over a fixed algebraically closed field k, with the Axiom of Choice. Classical varieties are separated and admit finite affine covers; they may be reducible or empty unless irreducibility is specified. Irreducible means nonempty. All fibres and points below are classical closed-point fibres and points.

Facts & Assumptions

Given: The objects and hypotheses in the statement.

[F1]

For a nonempty affine algebraic set X, dimX=dimk[X], where the right side is Krull dimension. For this comparison only, extend ring dimension to the zero ring by dim(0)=; then the equality also holds for X=. Work over a fixed algebraically closed field k, with the Axiom of Choice. Classical varieties are separated and admit finite affine covers; they may be reducible or empty unless irreducibility is specified. Irreducible means nonempty. All fibres and points below are classical closed-point fibres and points. (Affine geometric dimension equals ring dimension).

[F2]

If U is a nonempty open of an irreducible classical variety X, then dimU=dimX. Every proper closed subvariety ZX has dimZ<dimX. Work over a fixed algebraically closed field k, with the Axiom of Choice. Classical varieties are separated and admit finite affine covers; they may be reducible or empty unless irreducibility is specified. Irreducible means nonempty. All fibres and points below are classical closed-point fibres and points. (Nonempty opens preserve irreducible dimension).

[F3]

Let R be a Noetherian commutative ring, let I=(x1,,xn) be an ideal generated by n1 elements, and let p be a prime ideal minimal over I. Then ht(p)n. (Krull's height theorem).

[F4]

Let k be a field, let A be a finite-type k-domain, and let pSpec(A). Then ht(p)+dim(A/p)=dimA. (Height plus quotient dimension equals ambient dimension in an affine domain).

Proof

1.1

For r=0 the zero set is X and the bound is equality. Suppose r1 and fix a nonempty component Z. Choose a nonempty affine chart U meeting Z away from the other finitely many components of the zero set. Then ZU is a component of the affine zero locus. Both U and ZU have the dimensions of X and Z respectively.

F2
2.1

The prime p defining ZU is minimal over the ideal generated by the restrictions of the r functions in the Noetherian domain k[U]. Hence htpr. The height formula and geometric/ring comparison give dimZ=dimk[U]/p=nhtpnr. Zero or redundant equations cause no problem; if the zero set is empty there is no component to test.

F1F3F4step 1.1

Depends on

Used by

Dependency tree · two levels

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Sources