Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Blocks in a finite transitive action have a common size

Statement

Let G act transitively on a finite set Ω, and let B be a block system. Then any two blocks in B have the same finite cardinality. In particular, if BB, then Ω is a disjoint union of finitely many copies of B, so B divides Ω.

Facts & Assumptions

Given: A transitive action of G on a finite set Ω and a block system B.

[L1]

A transitive action sends any chosen point to any other point by some element of G (Left group actions, transitive actions, and faithful actions).

[L2]

A block system is a partition of Ω into blocks, and if B is a block then every translate gB is again a block (Blocks and block systems for a group action).

Proof

technique · direct
1.1

Let B,CB. Choose bB and cC. By transitivity there is gG with gb=c.

L1choose
2.1

Since gb(gB)C, the two blocks gB and C meet. Because B is a partition into blocks, they are equal.

step 1.1L2
3.1

The map BC, xgx, is a bijection because every group element acts bijectively on Ω. Hence B=C.

step 2.1algebra
4.1

As B and C were arbitrary, all blocks in B have the same size. Since the blocks are pairwise disjoint and cover the finite set Ω, the cardinality of any block divides Ω.

step 3.1given

Depends on

Used by

Dependency tree · two levels

3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources