Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passaudited 2026-09-07
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Boundary-defining functions exist locally and detect inward vectors

Statement

Every boundary point has a boundary-defining function; for any such ρ, a vector v is inward exactly when dρp(v)>0.

Facts & Assumptions

Given: A boundary point p of a smooth manifold M, a boundary chart at p, and, for the sign assertion, a boundary-defining function ρ near p and a vector vTpM.

[L1]

A boundary-defining function is nonnegative, vanishes exactly on the boundary, and has nonzero differential there (Boundary-defining functions).

[L2]

Inward, outward, and boundary-tangent vectors have respectively positive, negative, and zero last coordinate in a boundary chart (Inward, outward, and boundary-tangent vectors).

Proof

technique · direct
1.1

In the chosen boundary chart take ρ=xn. It is nonnegative, vanishes precisely on the face, and has nonzero differential, so it is a boundary-defining function by [L1].

givenL1construct
2.1

For any boundary-defining function ρ, its restriction to the face is zero, so dρp vanishes on the tangent hyperplane. Its derivative in the positive normal coordinate is nonnegative because ρ0 on the half-space and ρ(p)=0; by [L1] it is nonzero, hence positive. Therefore dρp(v) has the sign of the last coordinate of v, and [L2] gives dρp(v)>0 exactly for inward v.

givenL1L2step 1.1

Depends on

Used by

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Dependency tree · two levels

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Sources