Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-12
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Collapse does not in general split the abutment

Statement

Collapse does not in general split the filtered abutment.

Facts & Assumptions

Given: The degree-zero stalk of the filtered ℤ/4 in F1.

[F1]

ℤ/4 with its order-two subgroup has two ℤ/2 graded pieces and is not isomorphic to their direct sum (Isomorphic associated graded objects need not give isomorphic filtered objects).

[F2]

A degreewise finite filtered complex abuts to its image-filtered homology (Bounded filtered complex spectral sequence abuts to filtered homology).

[F3]

Collapse means all subsequent differentials vanish (Collapse at a page).

[F4]

Splitting an extension requires a section of the quotient (Extension problem of a convergent spectral sequence).

[F5]

A stalk complex has a single nonzero chain object and zero differential (Zero complex and stalk complex).

[F6]

The r-page is the specified filtered numerator/denominator quotient (R page of the spectral sequence of a filtered complex).

[F7]

The page differential is induced by the chain differential (The filtered differential induces d r on the r page).

Proof

technique · direct
1.1

Put the filtered A=ℤ/4 of [F1] in chain degree zero and zero elsewhere, using [F5]. Every differential of C is zero. Hence Ap,0r=FpA and the page denominator is Fp1A for every r, so the pages have ℤ/2 at (0,0) and (1,-1), zero elsewhere, and all page differentials vanish. Thus the sequence collapses from page zero by [F3].

F1F3F5F6F7
2.1

Its homology is A in degree zero with exactly the given filtration; finite convergence [F2] identifies these two stable pieces with its graded homology. The quotient A→A/{0,2}≅ℤ/2 cannot have a section: the image of 1 would have to be 1 or 3 modulo 4, but either doubles to 2, while a homomorphism from ℤ/2 must send 1 to an element killed by 2. Therefore the extension does not split in the sense of [F4].

F1F2F4step 1.1

Source notes

Weibel, §5.2 pp.123–124; the nonsplitting witness is computed here.

Depends on

Used by

Dependency tree · two levels

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Sources