Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01
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Before convergence, every CG denominator pkApk is positive

Statement

Assume the conjugate-gradient recurrence of The conjugate-gradient recurrence is defined through step k for a Hermitian positive-definite matrix A. If rk0, then pk0 and

pkApk=pkA2>0.

Facts & Assumptions

Given: A Hermitian positive-definite system Ax=b, a CG run through step k, and a nonzero residual rk.

[F1]

CG uses the recurrence αj=rj,rjApj,pj,rj+1=rjαjApj,βj=rj+1,rj+1rj,rj,pj+1=rj+1+βjpj with p0=r0 (The conjugate-gradient recurrence).

[L1]

For Hermitian positive-definite A, the energy norm satisfies uA2=Au,u, and it is positive on nonzero vectors (The energy inner product u,vA=Au,v and energy norm uA for a Hermitian positive-definite matrix).

Proof

technique · direct
1.1

We first show by induction on jk that pj,rj=rj,rj. For j=0 this is immediate from p0=r0 in [F1]. If it holds at j, then [F1] gives pj,rj+1=pj,rjαjpj,Apj=rj,rjαjpj,Apj=0, so pj+1,rj+1=rj+1,rj+1+βjpj,rj+1=rj+1,rj+1. Thus the identity holds for every jk.

F1inductionalgebra
2.1

At j=k, step 1.1 gives pk,rk=rk,rk>0 because rk0. Hence pk0. By [L1], pkApk=Apk,pk=pkA2>0, which is the desired positivity of the denominator.

L1step 1.1algebra

Depends on

Used by

Cited to discharge well-definedness by The conjugate-gradient recurrence.

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources