Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-09-05
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After block ordering, the decomposition matrix is block diagonal

Statement

If the ordinary irreducible characters and irreducible Brauer characters are ordered block by block, then the decomposition matrix becomes block diagonal.

Facts & Assumptions

Given: The decomposition matrix D=(dχφ).

[F1]

The entry dχφ records the multiplicity of the simple kG-module Sφ in the reduction of a stable lattice affording χ (Decomposition numbers and the decomposition matrix).

[L1]

Ordinary irreducibles and Brauer irreducibles each belong to unique blocks (Blocks partition the ordinary and Brauer irreducible characters).

Proof

technique · direct
1.1

If dχφ0, then by [F1] the simple module Sφ occurs in the reduction of a stable lattice affording χ. A composition factor of a module lies in the same block as the module itself, so χ and φ must belong to the same block.

F1L1givenalgebra
2.1

Therefore entries connecting two different blocks are zero. After reordering rows and columns by blocks, all nonzero entries lie inside the matching block sectors, so the matrix is block diagonal.

step 1.1algebra

Depends on

Used by

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources