Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-10
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Distance to a nonempty subset is one lipschitz

Statement

For nonempty A in connected M, x↦dg(x,A) is finite and 1-Lipschitz. More generally this holds on a component C with A∩C≠∅.

Facts & Assumptions

Given: x,y∈C and A∩C≠∅.

[F1]

Distance from a point to a subset: For A⊆M, define the distance to the subset by dg(x,A)=inf⁡a∈Adg(x,a), with inf⁡∅=+∞. Use def-extended-riemannian-distance-on-a-disconnected-manifold. If the component C of x meets A, all cross-component terms are infinite and may be discarded, so dg(x,A)=inf⁡a∈A∩Cdg(x,a)<∞. If A∩C=∅, every term is infinite and the value is +∞. In particular dg(x,A)=0 for x∈A, and dg(x,{a})=dg(x,a).

[F2]

Riemannian distance is a metric: dg is a finite metric on a connected Riemannian manifold.

Proof

technique · direct
1.1F1F2given

Fix one a0∈A∩C. Both distances to the set are bounded above by the finite point distances to a0, and below by zero. For every a∈A∩C, the triangle inequality gives dg(x,a)≤dg(x,y)+dg(y,a). Taking infima yields dg(x,A)≤dg(x,y)+dg(y,A).

2.1F1F2step 1.1∎

Interchange x,y and use symmetry to obtain the opposite inequality, so ∣dg(x,A)−dg(y,A)∣≤dg(x,y). All quantities subtracted are finite by step 1.1. On a component missing A the extended value is +∞ throughout, with no real-valued Lipschitz assertion.

Source locator

Lee, Chapter 13, pp.337–340, Proposition 13.25, Lemma 13.28 and Theorem 13.29; finite piecewise C1 refinements and pauses are treated explicitly here.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources