Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-22
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Distinct simple roots have nonpositive inner product

Statement

Let Φ⊆E be a reduced crystallographic root system with positive system Φ+ and simple roots Δ (Positive systems and simple roots). If α,β∈Δ are distinct, then (α,β)≤0; moreover α−β is not a root.

Facts & Assumptions

Given: Distinct simple roots α,β∈Δ of a reduced crystallographic root system Φ with positive system Φ+.

[L1]

A simple root is a positive root that is not a sum of two positive roots; Φ+ and Φ−=−Φ+ partition Φ (Positive systems and simple roots).

[L2]

If γ,δ∈Φ are nonproportional with (γ,δ)>0 then γ−δ∈Φ (Rank-two root-system classification).

Proof

technique · direct
1.1L1L2algebra

Assume (α,β)>0. Then α−β∈Φ by [L2], and since Φ is the disjoint union of its positive and negative roots, α−β is either positive or negative.

2.1L1step 1.1algebra

The two alternatives of step 1.1 are impossible: if α−β is positive, then α=(α−β)+β exhibits the simple root α as a sum of two positive roots; if α−β is negative, then β=(β−α)+α exhibits the simple root β as a sum of two positive roots.

3.1L1step 1.1step 2.1algebra∎

Hence (α,β)≤0. If α−β were a root, the same dichotomy would apply verbatim and contradict simplicity, so α−β∉Φ.

Depends on

Used by

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources