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PropositionStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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A finite sharply k-transitive action has order n(n-1)...(n-k+1)

Statement

Let G act sharply k-transitively on a finite set Ω of size n, with kn. Then G=n(n1)(nk+1).

Facts & Assumptions

Given: A sharply k-transitive action of G on a finite set Ω of size n, with kn.

[L1]

In a sharply k-transitive action, for any two ordered k-tuples of distinct points there is a unique group element carrying the first tuple to the second (Sharply k-transitive actions).

Proof

technique · direct
1.1

Fix one ordered k-tuple of distinct points (α1,,αk). Define Φ:GTk(Ω) by Φ(g):=(gα1,,gαk), where Tk(Ω) is the set of ordered k-tuples of distinct points of Ω.

L1construct
2.1

The map Φ is bijective: existence in [L1] makes it surjective, and uniqueness in [L1] makes it injective.

L1step 1.1
3.1

The set Tk(Ω) has n choices for the first entry, then n1 for the second, and so on down to nk+1 for the last. Hence Tk(Ω)=n(n1)(nk+1), and step 2.1 gives the same value for G.

step 2.1algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources