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Galerkin orthogonality turns residual orthogonality into -orthogonality of the error, and the Galerkin iterate is unique
Statement
Let be Hermitian positive definite, let , let be an initial guess, let , let be the exact solution of , and let . Then the following are equivalent:
- is orthogonal to in the standard inner product.
- is orthogonal to in the energy inner product.
When these conditions hold, the vector is the unique element of with that property.
Facts & Assumptions
Given: A Hermitian positive-definite system , an initial guess , , the exact solution , and a vector .
A Krylov Galerkin iterate is an element of whose residual is orthogonal to (The th Krylov Galerkin iterate in the affine space for a Hermitian positive-definite system).
The energy inner product is (The energy inner product and energy norm for a Hermitian positive-definite matrix).
Proof
For every , the identity gives by [L1]. Hence the residual is orthogonal to if and only if the error is -orthogonal to .
Suppose and both lie in and both satisfy the equivalent conditions from step 1.1. Then lies in , and both errors are -orthogonal to . Subtracting the two orthogonality relations gives Positive definiteness of the energy inner product therefore forces , so .
Depends on
Used by
Dependency tree · two levels
6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Magnus R. Hestenes and Eduard Stiefel, Methods of Conjugate Gradients for Solving Linear Systems (standard reference, not scraped)