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PropositionStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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The Galois correspondence exchanges composita with subgroup intersections and field intersections with generated subgroups

Statement

Let K/F be finite Galois, and let Ei=KHi correspond to subgroups HiGal(K/F) for i=1,2. Then

Gal(K/E1E2)=H1H2,

and

Gal(K/E1E2)=H1,H2.

Facts & Assumptions

Given: The compositum E1E2, the generated subgroup H1,H2 of The subgroup S generated by a subset, the cyclic subgroup g, and cyclic groups, and the subgroup intersection of The intersection of a nonempty family of subgroups of G is a subgroup of G.

[L1]

The assignments HKH and EGal(K/E) are mutually inverse inclusion-reversing bijections (The fundamental theorem of finite Galois theory).

Proof

technique · direct
1.1

An automorphism of K fixes E1E2 exactly when it fixes every element of both E1 and E2, exactly when it belongs to both H1 and H2. Therefore Gal(K/E1E2)=H1H2.

L1algebra
2.1

An element of K is fixed by H1,H2 exactly when it is fixed by every element of both generating subgroups, so KH1,H2=KH1KH2=E1E2. Applying [L1] gives the second formula. These membership equivalences also cover equal fields, the base and top fields, and trivial or full subgroups.

L1step 1.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources