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Functoriality with coefficient morphisms

Statement

Let f:(X,A)(Y,B) be a map of pairs.

  1. A coefficient morphism η:LfK induces f:Hn(X,A;L)Hn(Y,B;K).
  2. A coefficient morphism θ:fKL induces f:Hn(Y,B;K)Hn(X,A;L).

At a fixed space, both theories are covariant in coefficient morphisms. These maps preserve identities and composition. If H:f0f1 is a homotopy of pair maps, transport along tH(x,t) gives τH:f0Kf1K; the homology maps agree when η1=τHη0, and the cohomology maps agree when θ0=θ1τH.

Facts & Assumptions

Given: The map, local systems, and correctly directed coefficient morphism in the relevant clause.

[F1]

Homology and cohomology with local coefficients uses intrinsic local chains with coefficients at the first vertex and intrinsic local cochains with values at the first vertex.

[F2]

Local systems and pullback gives pullback transports and the naturality equation for coefficient morphisms.

Proof

technique · direct
1.1

Define (f,η)#(mσ)=ησ(e0)(m)(fσ). On the exceptional zeroth face, [F2] says ησ(e1)Tσ[0,1]L=Tfσ[0,1]Kησ(e0); all other faces use the same first vertex. Hence this is a chain map and carries the subcomplex on A into that on B, so [F1] gives the asserted f.

F1F2
1.2

For a cochain φ on Y, define ((f,θ)#φ)(σ)=θσ(e0)(φ(fσ)). The same naturality square, inverted on the exceptional face, makes this commute with coboundary. It preserves the relative kernel because f(A)B, and hence induces the asserted f. Taking f=1X proves covariance in a coefficient morphism for both theories.

F1F2
2.1

Substitution in the two displayed chain-level formulas proves the identity laws. For composable maps XfYgZ, the homology coefficient morphism is LfKfgN=(gf)N, and the cohomology coefficient morphism is the reverse composite; componentwise substitution proves the composition laws without a basepoint or lift choice.

F2step 1.1step 1.2
2.2

For a homotopy H, define (τH)x=TtH(x,t)K. A path square (s,t)H(γ(s),t) shows by its two boundary routes that these components satisfy the naturality equation, so τH is a coefficient isomorphism. Triangulate each prism Δn×I as in the ordinary prism operator and transport the coefficient from its initial first vertex along the corresponding prism edge. The usual oriented-prism cancellation is unchanged; the only new comparisons are transports along the two boundary routes of a triangular face, and those are equal because the face supplies an endpoint-fixed homotopy. Thus the resulting PH satisfies (f1,η1)#(f0,η0)#=PH+PH when η1=τHη0.

F1F2step 1.1
3.1

Precomposing a local cochain with the prism operator and applying the coefficient map in the reverse direction gives a cochain homotopy (f1,θ1)#(f0,θ0)#=PHδ+δPH when θ0=θ1τH. Chain- or cochain-homotopic maps induce equal maps on (co)homology by applying the identity to cycles/cocycles and observing that the difference is a boundary/coboundary. This proves the homotopy clauses. Empty pairs, zero systems, degree zero, degenerate simplices, and constant homotopies obey the same formulas, and no AC is used.

step 1.2step 2.2

Depends on

Used by

Dependency tree · two levels

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