Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The density line and its positive cone

Statement

The densities D(V) form a one-dimensional real vector space under pointwise operations. Evaluation on any basis is a linear isomorphism D(V)R. The nonzero nonnegative densities form a canonical positive ray.

Facts & Assumptions

[F1]

A signed one-density on a real vector space: For an n-dimensional real vector space V, a one-density is a real-valued function δ on ordered bases such that δ(vA)=detAδ(v)(AGL(n,R)). For n1 extend its value by zero to dependent n-tuples. For n=0 it is an arbitrary real scalar on the empty basis (the empty determinant is one). Write D(V) for these densities. Positive means strictly positive on every basis; nonnegative includes zero. Negative scalar multiples remain densities; positivity is extra structure on their one-dimensional real space.

Proof

Given: The objects and hypotheses in the statement above.

1.1

Fix a basis e (the empty basis when n=0). Every basis is uniquely eA for AGL(n,R). A density is determined by c=δ(e) since δ(eA)=cdetA. Conversely this formula, with zero on dependent tuples for n1, satisfies the required transformation law by multiplicativity of determinants.

F1
2.1

The formula is linear in c, so evaluation and its displayed inverse are linear bijections. Since detA>0, positivity is equivalent to c>0 and nonnegativity to c0, independently of the chosen basis. Thus the nonzero nonnegative densities are exactly one ray. For n=0 this says precisely that scalars form R.

step 1.1algebra

Depends on

Used by

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources