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An integral binary quadratic form is positive definite exactly when its leading coefficient is positive and its discriminant is negative

Statement

Let f(x,y)=ax2+bxy+cy2 be an integral binary quadratic form, and let Δ=b2−4ac be its discriminant. Then f is positive definite if and only if

a>0andΔ<0.

Facts & Assumptions

Given: The integral binary quadratic form f(x,y)=ax2+bxy+cy2 and its discriminant Δ=b2−4ac.

[F1]

A form is positive definite when f(x,y)>0 for every real pair (x,y)≠(0,0) (Positive-definite binary quadratic forms).

[F2]

The discriminant is Δ=b2−4ac (The discriminant of a binary quadratic form).

Proof

technique · direct
1.1F1

Suppose f is positive definite. Then a=f(1,0)>0 by [F1].

1.2F2givenalgebra

Conversely, suppose a>0 and Δ<0. For every real (x,y) one has 4af(x,y)=(2ax+by)2−Δy2 by direct expansion.

1.3givenalgebra

If (x,y)≠(0,0) and y=0, then x≠0 and f(x,0)=ax2>0 because a>0.

2.1F1F2step 1.1algebra

Also (−b2a,1)≠(0,0), so [F1] gives f(−b2a,1)>0. Multiplying by 4a>0 from step 1.1 yields − Δ=(2a(−b/(2a))+b)2−Δ>0, hence Δ<0.

2.2step 1.2givenalgebra

If (x,y)≠(0,0) and y≠0, then step 1.2 gives 4af(x,y)=(2ax+by)2+(−Δ)y2>0 because both summands are nonnegative and the second is positive.

3.1F1step 1.1step 2.1step 2.2step 1.3∎

Steps 2.2 and 1.3 cover every nonzero real pair, so f is positive definite by [F1]. Together with steps 1.1 and 2.1, this proves the criterion.

Depends on

Used by

Dependency tree · two levels

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Sources