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An integral binary quadratic form is positive definite exactly when its leading coefficient is positive and its discriminant is negative
Statement
Let be an integral binary quadratic form, and let be its discriminant. Then is positive definite if and only if
Facts & Assumptions
Given: The integral binary quadratic form and its discriminant .
A form is positive definite when for every real pair (Positive-definite binary quadratic forms).
The discriminant is (The discriminant of a binary quadratic form).
Proof
Suppose is positive definite. Then by [F1].
Conversely, suppose and . For every real one has by direct expansion.
If and , then and because .
Also , so [F1] gives . Multiplying by from step 1.1 yields , hence .
If and , then step 1.2 gives because both summands are nonnegative and the second is positive.
Steps 2.2 and 1.3 cover every nonzero real pair, so is positive definite by [F1]. Together with steps 1.1 and 2.1, this proves the criterion.
Depends on
Used by
Dependency tree · two levels
3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- William Stein, Elementary Number Theory and Elliptic Curves, Section 9.2.4 (standard reference, not scraped)
- Andrew Granville, Binary Quadratic Forms, Chapter 4 (standard reference, not scraped)