Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-generatedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Ranks of ordinals and hierarchy stages

Statement

In ZF, for every ordinal α, rank⁡(α)=α and rank⁡(Vα)=α.

Facts & Assumptions

Given: Work in ZF unless the statement explicitly weakens or supplements it; fix the objects and hypotheses of the statement.

[F1]

In ZF, for every set x and ordinal α, x∈Vα  ⟺  rank⁡(x)<α,x⊆Vα  ⟺  rank⁡(x)≤α. Thus rank⁡(x) is the least α with x⊆Vα, and rank⁡(x)=α iff x∈Vα+1∖Vα. (Rank characterizes hierarchy membership)

[F2]

In ZF without Foundation, every Vα is transitive and α≤β implies Vα⊆Vβ. Also Vα∩Ord⁡=α, and both α and Vα belong to Vα+1∖Vα. (Transitivity and growth of hierarchy stages)

Proof

1.1F1F2

By F2, α∈Vα+1∖Vα. The final equivalence in F1 therefore gives rank⁡(α)=α, including α=0.

2.1F1F2∎

By F2, Vα∈Vα+1∖Vα. Applying the same equivalence in F1 gives rank⁡(Vα)=α, including V0=∅.

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources