Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-31
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Shifted QR iteration preserves upper Hessenberg form

Statement

If H is upper Hessenberg and a shifted QR step factors HμI=QR using the standard adjacent-row Givens eliminations, then

H+:=RQ+μI

is again upper Hessenberg.

Facts & Assumptions

Given: An upper Hessenberg matrix H and a shifted QR factorisation HμI=QR built from adjacent Givens eliminations.

[L2]

Upper Hessenberg means all entries below the first subdiagonal vanish (Upper Hessenberg matrices and real symmetric tridiagonal matrices).

Proof

technique · direct
1.1

Because HμI is upper Hessenberg, each subdiagonal entry can be annihilated by an adjacent Givens rotation acting only on two consecutive rows. By [L3], the product of these rotations gives Q and an upper triangular R.

L2L3construct
2.1

Right-multiplying an upper triangular matrix by one adjacent Givens rotation can create a nonzero entry only one row below the diagonal in the two affected columns. Repeating this through the same adjacent sequence keeps RQ upper Hessenberg.

step 1.1algebra
3.1

Adding μI changes only diagonal entries, so [L1] and step 2.1 show that H+=RQ+μI is again upper Hessenberg.

L1step 2.1

Depends on

Used by

Dependency tree · two levels

10 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources