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Specialization at q=1 recovers the classical enveloping relations

Statement

Let (I,A,D,P,P∨,q) be a finite symmetrizable Cartan datum, A=Z[q,q−1], UA the integral form of The Lusztig divided-power integral form UA, and k a characteristic-zero field regarded as an A-algebra by q↦1. Let gder be the classical Lie algebra presented by generators ei,fi,hi with the Cartan and Serre relations, its Cartan being the span of the independent simple coroots (Serre presentation of a kac moody algebra).

(a) Halves. UA±⊗Ak≅U(n±)k by Fi↦fi, respectively Ei↦ei.

(b) Positive quotient. The quotient (UA⊗Ak)/(Kh−1:h∈P∨) is isomorphic to U(gder)k; in it Hˉi=Tˉi,0,1 is the classical coroot generator, Tˉi,c,t=(Hi+ct), and the positive toral quotient is k[Hi:i∈I] with kernel exactly (Kh−1:h∈P∨).

(c) Operator form. On every UA-stable label-graded lattice the quotient action of (b) is automatic: Kˉh=id, the Tˉi,c,t act by the integer binomials (⟨μ,hi⟩+ct), and all classical Cartan and Serre operator relations hold, without any unproved global Z[q,q−1]-freeness.

(d) Boundaries. The unquotiented specialization UA⊗Ak is not identified with U(gder)k: it retains toral characters, as the integral sl2-representation with E=F=0, K=−1 shows. Extra Cartan directions of a regular realization act diagonally on label-graded modules; they are not fabricated as generators of the toral integral form, and direct substitution q=1 into vanishing denominators qis−qi−s is never performed anywhere in this comparison.

Facts & Assumptions

Given: The integral form over A, the local DVR R=Q[q](q−1), a characteristic-zero field k with A→k, q↦1, and the classical presentation data of gder.

[F1]

The rational-local theorem: UA⊗AR=UR is the generated R-subalgebra; each UR±[±ν] is finite free with q=1 fibre the classical half U(n±); the toral R-basis is {Kc∏iKiδiHiti} with Hi=Ti,0,1; multiplication UR−⊗RUR0⊗RUR+→UR is an isomorphism; and the positive toral quotient is k[Hi] with Tˉi,c,t=(Hi+ct) and kernel exactly (Kh−1:h∈P∨) (Rational-local quantum halves and torus specialize at q=1(a)-(c)).

[F2]

The full positive quotient is U(gder)k: the specialized Serre, mixed and shifted toral relations give a surjection from the classical enveloping algebra, and the map is an isomorphism on each factor of the negative-toral-positive decompositions of [F1] and of the classical algebra (classical PBW); multiplication intertwines these tensor decompositions, so the surjection is injective (Rational-local quantum halves and torus specialize at q=1(c), Serre presentation of a kac moody algebra).

[F3]

The rank comparison used by [F1] is the published generic/classical rank theorem (i), which assumes AC; it is the only AC input (Generic quantum Serre halves have classical PBW ranks and a nondegenerate Hopf pairing, The Axiom of Choice).

[F4]

On a UA-stable label-graded lattice, Kˉh=id, Tˉi,c,t acts by (⟨μ,hi⟩+ct)∈Z, and the classical Cartan and mixed relations [Eˉi,Fˉj]=δijHˉi, [Hˉi,Eˉj]=aijEˉj, [Hˉi,Fˉj]=−aijFˉj hold (The q=1 toral specialization identifies the classical Cartan generators(b)).

[F5]

Gaussian binomials at integer labels are Laurent polynomials specializing to the ordinary binomials, hence give integer scalar operators; the Serre elements of the Drinfeld-Jimbo presentation specialize coefficientwise to the classical Serre elements (The quantum Pascal recurrences, the Gauss product formula and Gaussian integrality, Quantum integers, factorials, Gaussian binomials and divided powers at qi, The Drinfeld-Jimbo quantized enveloping algebra by generators and relations).

[F6]

The unquotiented specialization retains toral characters: for sl2, the assignment E=F=0, K=−1 is an integral representation whose toral binomials act by (−1)t(ct)-type scalars and whose K image at q=1 is −1≠1 (Rational-local quantum halves and torus specialize at q=1(c); Quantum weight modules, weights in P, and integrability for label-graded modules, where Kh acts by q⟨μ,h⟩↦1).

Verification

technique · localize to the DVR, invoke the rational-local theorem for the halves, torus and full positive quotient, invoke the graded-lattice lemma for the operator form, and record the two boundary warnings
1.1F1F3algebra

Halves and positive toral quotient. By [F1], localizing at R makes every [r]i! a unit, so each half is generated by its ordinary generators; the finite free components have q=1 fibres isomorphic to the classical halves, and the positive toral quotient is k[Hi] with Tˉi,c,t=(Hi+ct) and the stated exact kernel. Since k is an A-algebra through A→R→k, base change along A→k factors through R and gives (a) and the toral part of (b).

1.2F1F2F5algebra

The full positive quotient. By [F1] the multiplication map over R is an isomorphism, so after ⊗Rk the quotient (UA⊗Ak)/(Kh−1) has the vector-space decomposition U(n−)k⊗kk[Hi]⊗kU(n+)k; by [F2] the specialized relations give an isomorphism with U(gder)k. In this isomorphism Hˉi=Tˉi,0,1 corresponds to the classical coroot generator hi, and Tˉi,c,t=(Hi+ct); the kernel of the toral projection is exactly the ideal generated by the Kh−1. This proves (b).

1.3F4F5algebra

Operator form on graded lattices. Part (c) is [F4]: the specializations of Kh and Ti,c,t on a UA-stable label-graded lattice are the identity and the integer binomial scalars, and the mixed, Cartan and Serre relations hold as operator identities by reducing the integral relations; no freeness beyond the lattice's own graded structure is needed.

2.1F1F4F5F6algebra∎

Boundaries. The unquotiented specialization is strictly bigger than the positive quotient in general: the sl2 witness of [F6] has K acting by −1 after q=1, so it cannot factor through the quotient by K−1, and in particular the unquotiented specialization is not identified with U(gder)k. Extra Cartan directions of a regular realization act diagonally on label-graded modules through the labels ([F4]); they are not added as new algebra generators of the toral integral form, whose generators are the Kh±1 and the Ti,c,t only. All divisions in the argument were performed inside R on units; a vanishing denominator qis−qi−s is never substituted by q=1. This completes (d) and the proposition.

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Sources