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Tensor products and contractions of smooth tensor fields are smooth
Statement
The tensor product of smooth tensor fields is smooth. If a smooth mixed tensor field has at least one contravariant and one covariant slot, then contracting its first contravariant slot against its first covariant slot is smooth.
Facts & Assumptions
Given: Smooth tensor fields and , and a smooth mixed tensor field with at least one covariant and one contravariant slot.
Tensor-field smoothness is equivalent to smoothness of the local coefficient functions (Smoothness of a tensor field is equivalent to smooth coordinate components).
Tensor product is bilinear, and contraction is basis-independent (Tensor product of multilinear tensors is associative and bilinear, Contraction is independent of the basis formula).
Proof
In any chart, [L1] identifies , , and with families of smooth coefficient functions. By [L2], the coefficients of are finite sums of products of the coefficients of and . Those are smooth.
In the same chart, [L2] writes each contracted coefficient of as a finite sum of coordinate coefficients of . Because the contraction formula is basis-independent, these chartwise definitions glue. The resulting coefficient functions are smooth by [L1].
Therefore tensor products and the contraction defined above preserve smoothness.
Depends on
Used by
Dependency tree · two levels
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Sources
- John M. Lee, Introduction to Smooth Manifolds, 2nd ed. (standard reference, not scraped)