Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Absolute value of a top form as a density

Statement

For a smooth top form ω on M, pointwise absolute value defines a nonnegative continuous density ω, with ω=ω. It is smooth on the nonvanishing locus of ω but need not be smooth at its zeros.

Facts & Assumptions

[F1]

Density bundle and smooth density fields: For a smooth manifold Mn, with boundary allowed, the density bundle is DM=pMD(TpM). In coordinates x, let dx=dx1dxn be the density taking value one on the coordinate frame. On overlaps, dy=detDxydx. A smooth density is a section with smooth real coefficient in these frames. Its support is the closure of its nonzero locus. The absolute determinants are positive smooth transition functions and satisfy the cocycle identities by the chain rule. A countable atlas and thm-vector-bundle-construction-from-a-smooth-cocycle therefore give a smooth line bundle. For boundary charts the same gluing proof uses half-space product charts; smoothness of transitions follows from their local extensions, and Hausdorffness and second countability follow as for the supplied cocycle construction. The fibers are lines by prop-one-densities-form-a-one-dimensional-vector-space. When n=0 the empty frame trivializes DM=M×R.

Proof

Given: The objects and hypotheses in the statement above.

1.1

If ω=fdx1dxn, define ω=fdx. Taking absolute values in the determinant transformation law gives the density transition law, so these local expressions glue. Their coefficients are continuous and nonnegative, and changing ω to ω leaves them unchanged.

F1
2.1

Near a point where f0, its sign is constant, so f=f or f is smooth there. For ω=xdx on R, the coefficient x has left derivative 1 and right derivative 1 at zero, hence is not smooth. The zero form itself gives the smooth zero density; on a zero-manifold every function is smooth.

step 1.1algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources