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The connecting morphism vanishes for a chain-split short exact sequence
Statement
Let be a short exact sequence of complexes. If it admits either a chain section with or a chain retraction with , then for every .
Facts & Assumptions
Given: A short exact sequence of complexes.
A chain map is a degreewise morphism commuting with the differentials (Chain map).
The connecting morphism is induced from the preconnecting arrow on cycles (The connecting morphism in homology, The preconnecting arrow on cycles).
The associated homology sequence is exact (The long exact sequence in homology).
Proof
Suppose first that there is a chain section with . Functoriality of homology gives , so is epic. Exactness in [L3] gives , hence .
Suppose instead that there is a chain retraction with . Then , so is monic. Exactness in [L3] gives , and a morphism with zero image in an abelian category is zero. Thus the connecting morphism vanishes in either chain-split situation.
Depends on
Used by
Dependency tree · two levels
14 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Charles A. Weibel, Chapter 1 of An Introduction to Homological Algebra (standard reference, not scraped)