Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The total space of a rank-r bundle has dimension dim M + r

Statement

If π:EM is a smooth vector bundle of rank r and dimM=n, then dimE=n+r.

Facts & Assumptions

Given: A rank-r smooth vector bundle π:EM with dimM=n.

[L1]

Every point of E lies in a vector bundle chart identified with U×Rr over an open set UM (Vector bundle charts and transition functions).

Proof

technique · direct
1.1

Fix eE with base point p=π(e). Choose a chart of M sending a neighborhood of p diffeomorphically onto an open subset of Rn, and combine it with a vector bundle chart from [L1]. This identifies a neighborhood of e in E with an open subset of Rn×Rr.

L1given
2.1

Since Rn×RrRn+r, every point of E has a chart of dimension n+r. Therefore the total space E is an (n+r)-manifold.

step 1.1algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources