Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The total space of a rank-r bundle has dimension dim M + r

Statement

If π:E→M is a smooth vector bundle of rank r and dim⁡M=n, then dim⁡E=n+r.

Facts & Assumptions

Given: A rank-r smooth vector bundle π:E→M with dim⁡M=n.

[L1]

Every point of E lies in a vector bundle chart identified with U×Rr over an open set U⊆M (Vector bundle charts and transition functions).

Proof

technique · direct
1.1L1given

Fix e∈E with base point p=π(e). Choose a chart of M sending a neighborhood of p diffeomorphically onto an open subset of Rn, and combine it with a vector bundle chart from [L1]. This identifies a neighborhood of e in E with an open subset of Rn×Rr.

2.1step 1.1algebra∎

Since Rn×Rr≅Rn+r, every point of E has a chart of dimension n+r. Therefore the total space E is an (n+r)-manifold.

Depends on

Used by

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources