Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-generatedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Minimality and closure laws of TC

Statement

For every set a, TC(a) is transitive, contains a as a subset, and is contained in every transitive set T with aT. Moreover ab implies TC(a)TC(b), and TC(TC(a))=TC(a). In particular aTC({a}).

Facts & Assumptions

Given: Work in ZF unless the statement explicitly weakens or supplements it; fix the objects and hypotheses of the statement.

[F1]

For a set a, form a0=a and an+1=anan by recursion on ω. Set TC(a)=nωan. This is a set by the same recursion, Replacement and Union construction as finite predecessor closure, now starting from a rather than a singleton and using membership as the setlike relation. The convention is the least transitive superset of a; to include a itself as an element, use TC({a}). This construction does not assume Foundation. Conventions and prerequisites: lem-finite-predecessor-closure-is-a-set. (Transitive closure of a set)

Proof

1.1

The stage zero inclusion gives aTC(a). If zyTC(a), choose n with yan; then zanan+1. Thus the union is transitive. Equivalently, transitivity of a set T is the elementary condition TT.

F1
2.1

If aT and T is transitive, induction gives anT: the successor follows from anTT. Union over n proves minimality.

F1step 1.1
3.1

For ab, the transitive set TC(b) contains a, so minimality proves monotonicity. Applying minimality with T=TC(a) gives one idempotence inclusion and step 1.1 gives the other. Finally a{a}TC({a}).

step 1.1step 2.1

Depends on

Used by

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources