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Truncated SVD and Tikhonov regularisation act as hard and smooth spectral filters on the singular components

Statement

Let F{R,C}, let AMm×n(F) have singular value decomposition A=UΣV, let bFm, let τ0, and let λ>0. In singular-value coordinates, applying the two filters to b gives the following coefficients: truncated SVD multiplies the ith singular component by

gτ(σi)={σi1,σi>τ,0,σiτ,

whereas Tikhonov regularisation multiplies it by gλ(σi)=σi/(σi2+λ). Thus truncated SVD is a hard spectral filter and Tikhonov regularisation is a smooth spectral filter.

Facts & Assumptions

Given: A scalar field F{R,C}, a singular value decomposition A=UΣV, a right-hand side bFm, a threshold τ0, and a parameter λ>0.

[L1]

The truncated pseudoinverse replaces retained singular values by their reciprocals and discards the rest (The truncated singular-value pseudoinverse obtained by discarding singular values below a declared numerical-rank threshold).

[L2]

Tikhonov regularisation scales the ith singular direction by σi/(σi2+λ) (Tikhonov regularisation scales each singular component by the filter factor σ/(σ2+λ)).

Proof

technique · direct
1.1

By [L1], applying Aτ+ to b=ib,uiui gives Aτ+b=σi>τ1σib,uivi. Thus the filter is gτ(σi) with a hard cutoff at τ.

L1algebra
1.2

By [L2], the Tikhonov solution is xλ=σi>0σiσi2+λb,uivi. Hence every nonzero singular direction is retained but damped smoothly according to gλ(σi), while zero singular directions have filter value gλ(0)=0.

L2algebra
2.1

Step 1.1 is the truncated-SVD filter and step 1.2 is the Tikhonov filter, so the two methods are hard and smooth spectral filters respectively.

step 1.1step 1.2

Depends on

Used by

Dependency tree · two levels

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Sources