Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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The vector annihilator is the unique monic generator of AnnT(v) and divides the minimal polynomial

Statement

For an endomorphism T of a finite-dimensional vector space and vV, AnnT(v) is a nonzero ideal of F[x]. It has a unique monic generator mT,v, and p(T)v=0mT,vp. Moreover mT,vμT. In particular mT,0=1.

Facts & Assumptions

Given: A finite-dimensional endomorphism T and a vector v.

[L1]

The annihilator ideal is AnnT(v)={p:p(T)v=0} (Cyclic subspaces, cyclic vectors, and vector annihilators).

[L3]

Every ideal of F[x] is principal (For every field F, F[x] is a principal ideal domain).

Proof

technique · direct
1.1

Linearity of polynomial evaluation shows that [L1] is closed under addition and under multiplication by arbitrary polynomials, so it is an ideal; it is nonzero because [L2] puts μT in it.

L1L2algebra
2.1

By [L3] the ideal is (a) for a nonzero polynomial a; scaling by the inverse of its leading coefficient gives a monic generator mT,v, and two monic generators of one ideal are associates and hence equal.

step 1.1L3algebra
3.1

Membership in (mT,v) is exactly divisibility by mT,v, proving the displayed equivalence. Since μT belongs to the ideal, mT,vμT; if v=0, the ideal contains 1 and its monic generator is 1.

step 1.1step 2.1L1L2

Depends on

Used by

Cited to discharge well-definedness by Cyclic subspaces, cyclic vectors, and vector annihilators.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 37 results over 7 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources