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PropositionStatement: AI-adaptedProof: AI-adaptedPipeline-generatedaudited 2026-09-07
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Yoneda product is composition in the derived category

Statement

Assume DC, set-sized extension classes, and enough projectives with supplied resolutions, or dually enough injectives with supplied resolutions. Normalize the image of a short extension to be its connecting arrow in the cone convention of this page, and the image of a higher extension to be the shifted composite of the connecting arrows of its short exact pieces. With this normalization the Yoneda-class bijection is YExtn(M,N)HomD(M,N[n]) for n1. If αYExtp(M,L) and βYExtq(L,N), their splice corresponds to β[p]α:MN[p+q]; degree-zero maps act by pullback and pushout, with identity units.

In particular, for e:0AZB0 and e:0BuZC0, the splice is zero in Ext2(C,A) if and only if there is an extension 0AWZ0 whose pullback along u is e. Equivalently there is a commutative diagram of these two rows, with vertical maps 1A,ZW,u, whose middle and right columns are 0ZWC0 and 0BZC0.

Facts & Assumptions

Given: The Axiom of Dependent Choice, set-sized extension classes, and either enough projectives with supplied resolutions or enough injectives with supplied resolutions; objects and extension classes as in the statement.

[F1]

Classical Ext identifies naturally with derived-category Hom via the chosen one-sided resolutions (Ext is hom in the derived category).

[F2]

A short exact sequence of complexes gives a distinguished triangle via its cone-to-quotient map (Canonical truncations fit a distinguished triangle).

[F4]

Under DC, set-sized extension classes, and the stated one-sided resolution data, higher Yoneda Ext agrees with that classical Ext (Higher Yoneda Ext agrees with derived Ext).

[F5]

Both representable Hom sequences of a distinguished triangle are exact (Long exact Hom sequences of a distinguished triangle).

Proof

1.1

For an extension 0NEn1E0M0, let K0=M, Kn=N, and use its successive images to form short exact sequences ej:0Kj+1EjKj0 for 0j<n. Let bj:KjKj+1[1] be the connecting arrow from [F2]. Define Θ(E)=bn1[n1]b1[1]b0. Naturality of [F2] gives a commuting diagram of these arrows for any map of extensions fixing the endpoints, so Θ is constant on the generated Yoneda equivalence relation. The same naturality gives endpoint pullback and pushout compatibility. Direct sums of the short exact pieces give direct sums of their arrows; diagonal pullback and codiagonal pushout therefore make Θ additive for Baer addition.

F2F4algebra
1.2

Here is the degree-one comparison explicitly in the projective lane. For 0NiEM0, lift P0M to v:P0E and write vd1=ic with c:P1N. The cone of i has N in degree 1, E in degree zero, and differential i. The map PCone(i) with components c,v in degrees 1,0 is a complex map over M. Projection to N[1] gives the cocycle c. Thus the connecting arrow is the roof of c, and in particular is exactly the degree-one map used to define Θ, without an unproved appeal to the abstract Ext/Hom isomorphism. In the injective lane extend NI0 to w:EI0 and factor dw=tq through q:EM. The identity ptq after mapping N[1]I[1] is witnessed on the cone by the homotopy with component w:EI0; hence the connecting arrow is represented by t:MI[1]. This explicit sign is part of our normalization.

F1F2F4algebra
2.1

We verify bijectivity without assuming that an arbitrary natural Ext/Hom identification preserves products. In the projective lane let Kj=ΩjM in the supplied resolution. Exactness of [F5] for K1P0MK1[1] gives HomD(M,N[1]) as the quotient of Hom(K1,N) by restrictions from P0, because positive Ext from the projective P0 vanishes by [F1]. The quotient map sends h to h[1]b0. By the pushout construction in [F4], this is exactly Θ of the pushout extension. In degree n, that same construction identifies Yoneda classes with Hom(Kn,N) modulo restrictions from Pn1: a resolution cocycle factors through Kn, and a coboundary is precisely such a restriction. The degree-one quotient for 0KnPn1Kn10, followed by the connecting isomorphisms HomD(Kj,N[r])HomD(Kj1,N[r+1]) for r>0, identifies this quotient bijectively with HomD(M,N[n]). Each isomorphism follows from [F5] and the vanishing of both adjacent positive Hom groups from Pj1 by [F1]. Their composite is exactly the formula in step 1.1 for the pushout extension.

F1F4F5step 1.1step 1.2algebra
2.2

In the injective lane put C0=N and Cj+1=coker(CjIj) in the supplied coresolution. The dual construction in [F4] identifies degree-n Yoneda classes with Hom(M,Cn) modulo maps factoring through In1Cn. Apply [F5] to Cn1In1CnCn1[1] to identify this quotient with HomD(M,Cn1[1]). The subsequent connecting isomorphisms identify it with HomD(M,N[n]), since both neighboring positive Hom groups into each injective vanish by [F1]. On the pullback extension supplied by [F4], naturality of [F2] makes the composite exactly Θ. Thus the same intrinsic Θ is bijective in either lane, including when both are available.

F1F2F4F5step 1.1algebra
3.1

The short exact pieces of a splice are the pieces of its two factors in order. The definition in step 1.1 therefore gives Θ(βα)=Θ(β)[p]Θ(α), using associativity of composition and [p][q]=[p+q]. This also shows that the bijection is independent of the resolution used to prove its bijectivity. Degree-zero endpoint maps act by pullback and pushout by step 1.1, and identities act as units.

step 1.1step 2.1step 2.2algebra
4.1

Apply HomD(,A[1]) to the triangle BZCB[1] of e. Its connecting arrow is Θ(e) by definition and step 1.2. By [F5] the kernel of the map from HomD(B,A[1]) to HomD(C,A[2]) is the image of restriction from Z; the map is shifted composition with Θ(e), up to an irrelevant overall rotation sign. By step 3.1 its kernel is precisely the zero-splice condition. Bijectivity and pullback naturality of Θ give the asserted extension over Z, in both directions. Its pullback middle object is isomorphic to Z by equivalence of short extensions. The kernel of WZC is that pullback and the composite is epic, yielding 0ZWC0. Conversely exactness of the stated diagram identifies Z with this kernel and hence with the pullback.

F2F5step 1.2step 2.1step 2.2step 3.1algebra

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