Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A zero object supplies a unique compatible system of zero morphisms

Statement

A chosen zero object 00 in a category supplies a unique compatible system of zero morphisms.

Facts & Assumptions

Given: A zero object 00 in a category C\mathcal C.

[L1]

A zero object is both initial and terminal, so there are unique arrows A0A\to0 and 0B0\to B for every A,BA,B (Initial object, terminal object, and zero object).

[L2]

A system of zero morphisms must absorb composition on either side (Category with zero morphisms).

Proof

technique · direct
1.1

Define 0A,B0_{A,B} as the composite of the unique arrows A0A\to0 and 0B0\to B supplied by [L1].

givenL1
2.1

For f:AAf:A'\to A, both 0A,Bf0_{A,B}\circ f and 0A,B0_{A',B} factor through 00 using the unique arrow A0A'\to0, so they are equal; the same uniqueness proves g0A,B=0A,Bg\circ0_{A,B}=0_{A,B'}.

step 1.1L1L2
3.1

Any compatible zero family must have 0A,B=00,B0A,00_{A,B}=0_{0,B}\circ0_{A,0}, and both factors are the unique arrows to and from 00, so the family of step 1.1 is unique.

step 2.1L1L2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 7 results over 5 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources