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RemarkRemark: Literature-sourcedProof: Not applicablePipeline-generatedjudge pass (gpt-5.6-terra)
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Carleson hunt does not include the lone endpoint

Statement

Assume AC as in the Kolmogorov construction. Its L1(T) witness excludes a bound for the Fourier partial-sum maximal operator on all of L1. The proposed Carleson–Hunt theorem concerns only 1<p<; this endpoint observation does not establish any of those positive bounds.

Facts & Assumptions

Given: Normalized Haar measure on the circle and the Kolmogorov witness f.

[F1]

The locally authored conclusion of Kolmogorov lone fourier series diverges almost everywhere gives fL1 with unbounded symmetric partial sums almost everywhere. The unavailable original backing was separately resolved by the owner using the complete local proof; no original-source retrieval is claimed.

[F2]

The Axiom of Choice is inherited from the countable construction of that witness.

Proof

1.1

Put Mf=supN0SNf. Each finite partial sum is measurable, hence this countable supremum is measurable. By F1 it equals infinity outside a null set on a space of measure one. For every positive integer k, the nonnegative simple function k on that conull set is bounded above by Mf, so the definition of the nonnegative integral gives Mfk. Consequently Mf1=.

F1F2givenalgebra
2.1

Since f1< by F1, step 1.1 contradicts every proposed finite-constant inequality Mh1Ch1 for all hL1. It also contradicts every finite weak-(1,1) constant: m{Mf>t}=1 for all t, whereas Cf1/t<1 for sufficiently large t. Thus neither assertion follows by adjoining the endpoint to the proposed positive-p range.

F1step 1.1algebra

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