Alphabeta Math
RemarkSession-authored (Fable 5 assisted) sources checked 2026-07-29 not proved here
Recorded, not proved here. This statement is included so the library can refer to it honestly, with a citation to the literature. It is not proved anywhere in this library: the track that would prove it has not been developed here yet.

Sierpiński 1947: the generalised continuum hypothesis implies the Axiom of Choice

Statement

Over ZF, the generalised continuum hypothesis implies the Axiom of Choice.

Precisely: assume ZF, and assume GCH in the choice-free form "for every infinite set AA there is no set BB with ABP(A)A \prec B \prec \mathcal{P}(A)", where XYX \prec Y means XX injects into YY but not conversely. Then every set can be well-ordered, and so the Axiom of Choice holds.

The argument (Lindenbaum and Tarski announced it in 1926; Sierpiński gave the published proof in 1947) runs through Hartogs numbers. For a set AA let (A)\aleph(A) be the least ordinal not injecting into AA, which exists in ZF. One shows in ZF that (A)P(P(P(A)))\aleph(A) \preceq \mathcal{P}(\mathcal{P}(\mathcal{P}(A))), and then uses GCH three times, on AA, on P(A)\mathcal{P}(A) and on P(P(A))\mathcal{P}(\mathcal{P}(A)), to force AA into bijection with an ordinal.

Remarks

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