Alphabeta Math
RemarkRemark: AI-adaptedProof: Not applicableSession-authored (Fable 5 assisted)verified 2026-08-09 (gpt-5.6-terra-codex-subscription)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced — the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted — a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated — a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Selected sums and products on this page that are proved to exist without being evaluated, and what their evaluation waits for

Remark

A convergence test proves that a limit exists; it does not produce the limit. On this page that gap is systematic, and this remark records the principal places where a familiar value or formula is deferred and what would close it. Every scope statement below is relative to the reading order: the material named is developed elsewhere in this library, later than this page, and nothing here says it is absent from the library.

The alternating harmonic series. The alternating series test: if (bk)(b_k) is nonincreasing with bk0b_k \to 0 then k(1)kbk\sum_{k} (-1)^{k} b_k converges, the sum lies between any two consecutive partial sums, and the error after nn terms is at most bnb_n proves that j0(1)j/(j+1)\sum_{j \ge 0} (-1)^j/(j+1) converges, and its error bound pins the sum between consecutive partial sums; the companion examples page uses that to prove the sum lies strictly between 1/21/2 and 11. No closed expression for the sum is given, and none can be given here: the classical value is a logarithm, and the logarithm is introduced later in the reading order. So the sum is named, bracketed, and left unevaluated.

The two-positive-one-negative rearrangement. The same is true one level up. The companion examples page proves that taking two positive terms for each negative one produces a convergent rearrangement whose sum is 3/23/2 times the sum of the original series. That statement is exact and complete as it stands, and it is deliberately relative: it compares two sums rather than evaluating either. The familiar form of the same fact multiplies a logarithm by 3/23/2, and it becomes available at the same later point.

The refined criterion for infinite products. For pk0p_k \ge 0 the product (1+pk)\prod (1 + p_k) converges iff pk\sum p_k converges, with 1+k<npkk<n(1+pk)1/(1k<npk)1 + \sum_{k<n} p_k \le \prod_{k<n}(1+p_k) \le 1/\bigl(1 - \sum_{k<n} p_k\bigr) when k<npk<1\sum_{k<n} p_k < 1; for 0pk<10 \le p_k < 1 the product (1pk)\prod (1 - p_k) converges iff pk\sum p_k converges and its partial products tend to 00 otherwise; and pk\sum |p_k| convergent implies (1+pk)\prod (1+p_k) convergent settles (1+pk)\prod(1+p_k) completely for pk0p_k \ge 0, settles (1pk)\prod(1-p_k) for 0pk<10 \le p_k < 1, and proves that pk\sum |p_k| convergent forces (1+pk)\prod(1+p_k) convergent. It does not settle the remaining case: a signed sequence (pk)(p_k) with pk\sum p_k convergent but pk\sum |p_k| divergent. The classical criterion there is that (1+pk)\prod(1+p_k) converges exactly when pk2\sum p_k^{2} converges. A standard proof expands log(1+x)\log(1+x); that route belongs with the logarithm, later in the reading order. The gap is not hypothetical: the companion examples page exhibits a signed sequence with pk\sum p_k convergent whose partial products tend to 00.

Rearrangement beyond R\mathbb{R}. The Riemann series theorem: a conditionally convergent real series has, for every cRc \in \mathbb{R}, a rearrangement with sum cc, and rearrangements diverging to ++\infty, to -\infty, and oscillating with any prescribed lim inflim sup\liminf \le \limsup in R\overline{\mathbb{R}} and For a series of real numbers, unconditional convergence and absolute convergence are the same property together answer the rearrangement question for real series completely. The corresponding question for series of vectors is raised, and left open at this point in the reading order, in The same question in Rd\mathbb{R}^d: what the set of rearrangement sums looks like, and why that answer is not reachable at this point in the reading order, which states no theorem about it.

Two places where existence is constructive but no formula is claimed. Base-bb expansions: for an integer b2b \ge 2 every x[0,1)x \in [0,1) is the sum of j0dj/bj+1\sum_{j \ge 0} d_j / b^{\,j+1} for digits dj<bd_j < b, and the digit sequence is unique among those that are not eventually constantly b1b-1 produces, for every x[0,1)x \in [0,1), its digit sequence in base bb, by a recursion that depends on xx; it gives no closed expression for the digits of any particular real, and it claims none. Likewise The Riemann series theorem: a conditionally convergent real series has, for every cRc \in \mathbb{R}, a rearrangement with sum cc, and rearrangements diverging to ++\infty, to -\infty, and oscillating with any prescribed lim inflim sup\liminf \le \limsup in R\overline{\mathbb{R}} produces, for each prescribed target, a bijection of N\mathbb{N} defined by a recursion over the terms of the series; no formula for that bijection is given, and the theorem asserts only that one exists. In both cases the construction is fully determined by the data, with no choice made anywhere, which is a stronger statement than mere existence and a weaker one than a formula.

What this list does not claim. It is not a census of every convergence result on the page. In particular, the Dirichlet, alternating-series, and Abel tests and their worked applications establish additional convergence without evaluating a numerical sum; their purpose here is to supply convergence criteria, not to flag a familiar value whose evaluation waits for a later object. Among the structural comparison theorems, Dirichlet's rearrangement theorem: an absolutely convergent series converges unconditionally, and every rearrangement of it has the same sum, Mertens' theorem: if ak\sum a_k converges absolutely to AA and bk\sum b_k converges to BB, their Cauchy product converges to ABAB, If ak\sum a_k and bk\sum b_k both converge absolutely then their Cauchy product converges absolutely, with sum ABAB, Grouping: if ak\sum a_k converges and (nj)(n_j) is strictly increasing with n0=0n_0 = 0, the series of blocks k=njnj+11ak\sum_{k=n_j}^{n_{j+1}-1} a_k converges to the same sum and Fubini for double series: if ijaij\sum_i \sum_j |a_{ij}| converges then both iterated sums and the sum along every bijection NN×N\mathbb{N} \to \mathbb{N} \times \mathbb{N} converge to one and the same value identify sums with one another and evaluate nothing, which is exactly what makes them usable wherever the sums themselves are unknown.

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Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 119 results over 26 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources