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A bounded below complex of injectives is homotopically injective
Statement
A bounded-below cochain complex of injective objects is K-injective. Assume dependent choice for the countable successive homotopy extensions, or supply those extensions as data.
Facts & Assumptions
Given: A bounded-below cochain complex of injective objects is K-injective. Assume dependent choice for the countable successive homotopy extensions, or supply those extensions as data.
An injective object extends maps from a subobject to the ambient object (Injective object).
K-injectivity is vanishing of Hom from every acyclic complex into every shift of the target (Homotopically injective bounded below complex).
DC supplies a sequence extending successive choices on a nonempty set (The axiom of dependent choice: a relation in which every element is related to something admits an -indexed chain).
Proof
Let be acyclic and a chain map. Choose with for and set equal to zero for . The equation holds below . In particular it is valid for zero complexes.
If the equation holds below , then vanishes on by the chain-map identity. Since is acyclic this image equals , so factors through . Injectivity of extends it to . This establishes the equation in degree .
Apply DC to the set of finite partial homotopies with the entire extension relation, or take the supplied successive extensions. The resulting homotopy makes zero in . Apply the same argument to every shift , which remains bounded below and termwise injective. This is the K-injective condition.
Depends on
Used by
Dependency tree · two levels
10 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- 13.18.3–13.18.8; W 10.4.8 for the equivalence (standard reference, not scraped)