Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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A bounded below complex of injectives is homotopically injective

Statement

A bounded-below cochain complex I of injective objects is K-injective. Assume dependent choice for the countable successive homotopy extensions, or supply those extensions as data.

Facts & Assumptions

Given: A bounded-below cochain complex I of injective objects is K-injective. Assume dependent choice for the countable successive homotopy extensions, or supply those extensions as data.

[F1]

An injective object extends maps from a subobject to the ambient object (Injective object).

[F2]

K-injectivity is vanishing of Hom from every acyclic complex into every shift of the target (Homotopically injective bounded below complex).

[F3]

Proof

1.1

Let A be acyclic and f:AI a chain map. Choose a with In=0 for n<a and set hn:AnIn1 equal to zero for na. The equation fn=dIhn+hn+1dA holds below a. In particular it is valid for zero complexes.

givenalgebra
2.1

If the equation holds below n, then un=fndIn1hn vanishes on imdAn1 by the chain-map identity. Since A is acyclic this image equals kerdAn, so un factors through imdAnAn+1. Injectivity of In extends it to hn+1:An+1In. This establishes the equation in degree n.

F1step 1.1algebra
3.1

Apply DC to the set of finite partial homotopies with the entire extension relation, or take the supplied successive extensions. The resulting homotopy makes f zero in K. Apply the same argument to every shift I[r], which remains bounded below and termwise injective. This is the K-injective condition.

F2F3step 2.1

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