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A square with monic legs is a pullback exactly when it identifies the source with the intersection subobject
Statement
Consider a commutative square in an abelian category
whose right and bottom legs are monomorphisms. Let be the intersection of the subobjects represented by and . Then the square is a pullback if and only if the induced morphism is an isomorphism.
Facts & Assumptions
Given: The displayed commutative square with monic right and bottom legs.
In an abelian category, pullbacks of cospans exist and are computed by the construction of A pullback is the kernel of the difference of the two legs, and dually for pushouts.
An intersection of two subobjects is their greatest lower bound in the subobject order (Intersection of a supplied family of subobjects as its greatest lower bound, Subobjects and quotient objects form oppositely oriented partially ordered collections).
Proof
By [L1], the pullback of the two monics and exists. Because the square defining is a common lower bound of and , and every other common lower bound factors uniquely through that pullback, [L2] says that represents their intersection subobject.
If the displayed square is a pullback, then its source is another representative of the same greatest lower bound from step 1.1. Therefore the induced morphism is an isomorphism.
Conversely, if the induced map is an isomorphism, then composing the pullback square representing from step 1.1 with that isomorphism yields the displayed square. Pullbackness is invariant under replacing the corner object by an isomorphic one, so the displayed square is a pullback.
Depends on
- In a pullback square, the induced map on the kernels of the two parallel arrows is an isomorphism
- Intersection of a supplied family of subobjects as its greatest lower bound
- Subobjects and quotient objects form oppositely oriented partially ordered collections
- A pullback is the kernel of the difference of the two legs, and dually for pushouts
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Junhan Tan, The Freyd-Mitchell Embedding Theorem, Theorem 2.5 (standard reference, not scraped)